9b^2-625=0

Solution for 9b^2-625=0 equation:

9b^2-625=0

a = 9; b = 0; c = -625;
Δ = b2-4ac
Δ = 02-4·9·(-625)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*9}=\frac{-150}{18}
=-8+1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*9}=\frac{150}{18}
=8+1/3
$